Possibly, they use very large pixels (and optics). On the bottom of the poster, they mention 491 x 171 um2 pixel size. This can compensate for the low PDE.
Two points: - the system has a relatively large aperture to compensate the PDE. - 20 shots are necessary for 30FPS @ 500kHz, more shots result in better images at lower framerates (or smaller frames at same frame rate.)
Their numbers do not make sense to me. In the original poster, it says that FOV is 80deg x 5deg, angle of view is 0.1x0.1, and it runs at 30fps. If the range is 300m, the maximum repetition rate is 500kHz. Then to scan 800x50 points at 30fps, each point only get 0.42 shot.
It's a line scanner: the frame consists of 800 lines illuminated in parallel, therefore the number of shots is calculated as: 500kHz/(30 x 800) = 20 The vertical AoV per pixel is 5/16 = 0.312
The numbers in the multi-shot image are misleading. Given the PDE being 9%, to receive at least 20 shots, more than 200 shots have to be projected.
ReplyDeletePossibly, they use very large pixels (and optics). On the bottom of the poster, they mention 491 x 171 um2 pixel size. This can compensate for the low PDE.
DeleteTwo points:
Delete- the system has a relatively large aperture to compensate the PDE.
- 20 shots are necessary for 30FPS @ 500kHz, more shots result in better images at lower framerates (or smaller frames at same frame rate.)
Their numbers do not make sense to me. In the original poster, it says that FOV is 80deg x 5deg, angle of view is 0.1x0.1, and it runs at 30fps. If the range is 300m, the maximum repetition rate is 500kHz. Then to scan 800x50 points at 30fps, each point only get 0.42 shot.
ReplyDeleteIt's a line scanner: the frame consists of 800 lines illuminated in parallel, therefore the number of shots is calculated as: 500kHz/(30 x 800) = 20
DeleteThe vertical AoV per pixel is 5/16 = 0.312
If 800 lines are illuminated in parallel, 800 pixels are needed. And they must be in horizontal direction.
Deleteplease ignore my previous post of 800 pixels.
Delete