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Saturday, August 29, 2020

Photonis Demos Color Night Imaging at 0.01 Lux

Photonis publishes a demo of its Nocturn color camera at 0.01 Lux scene illumination.

"The NOCTURN Color models are powered by the proprietary KAMELEON imaging sensor, a solid-state sensor that offers less than 4e- read noise, with SXGA (1280×1024) resolution at frame rates up to 100 Hz. The KAMELEON sensor provides large 9.72µm pixels with microlenses for optimum quantum efficiency in excess of 60%, providing high-resolution low light color images that extend the vision of the human eye."


13 comments:

  1. Crazy performance!!!
    Is this export controlled?

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  2. How many photons hit a 10x10u pixen in lets say 10ms when a 0.01 lux illuminated scene is captured? 25ke full well, lets say x25 gain, so a signal of 1000e- for s saturated pixel. How many photons cross a 10x10u area in 10ms at 0.01lux? Just a ballpark estimation ;-)

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    Replies
    1. i (i posted the question above) tried to retrace the '40 photons'

      1lux = 1 lumen over 1 m^2
      1watt = 683lumen (for 555nm)
      so 1lux = (1/683)W/m^2 = 1.5x10^-3 W/m^2 = 1.5x10^-15W/um^2
      PhotonEnergy Ep = hc/lambda = (6.6 10^-34[Js] * 300 * 10^6 [m/s]) / 555*10^-9 (m) = 3.6 *10^-19
      PhotonCount Pc = 1.5x10^-15[W/um^2] / 3.6 *10^-19 = 4100

      so about 4000 photons/sec for 1 lux per um^2, right? or 4 per ms. For a 10x10u pixel 400 per ms or 4000 for 10ms. For 0.01 lux 40 photons. Assuming a high QE of lets say 80%, this results in about 30 electrons per pixel during integration time.

      https://en.wikipedia.org/wiki/Luminous_flux
      https://de.wikipedia.org/wiki/Lichtstrom
      https://en.wikipedia.org/wiki/Illuminance
      https://en.wikipedia.org/wiki/Photon_energy

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    2. You have forgotten that 0.01 is illumination on the scene. To get the value on the sensor, you have to multiply 1/4F2, roughly 1/10 for F=1.4.

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  3. Yes, 40 photons. If QE=60%, 24 electrons.

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  4. Our worldwide patented Kameleon technology is indeed great! It is used in a lot of different applications around the world and is export free.
    Contact us for more détails!
    PHOTONIS TEAM

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    Replies
    1. Great! Do you have the patent no please?

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  5. Pixel Pitch = 9.7um
    Pixel Area = 94.1e-12m2
    W/lux for 550nm = 1/683
    Lux on sensor = 0.01/10 (F1.4)
    A/W at 550nm = 0.44A/W
    QE = 0.6
    Exposure Time = 10mS
    ==> 2.29 electrons

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  6. Where is photon noise at such low light level?

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  7. Hey guys, camera lens have focusing function. let's say F1.4, it should be x10 photons not /10. But considering object have 1/10 reflectivity . It should be 40x10/10=40 photons.

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    Replies
    1. Sorry, but higher f-no means smaller aperture and less light. So 1/8. Otherwise all the camera phones would use pinhole optics with great depth of field and life would be easy.

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